(1-x)=3x^2-4x+3

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Solution for (1-x)=3x^2-4x+3 equation: 



(1-x)=3x^2-4x+3

We move all terms to the left:

(1-x)-(3x^2-4x+3)=0

We add all the numbers together, and all the variables

(-1x+1)-(3x^2-4x+3)=0

We get rid of parentheses

-3x^2-1x+4x+1-3=0

We add all the numbers together, and all the variables

-3x^2+3x-2=0

a = -3; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·(-3)·(-2)
Δ = -15
Delta is less than zero, so there is no solution for the equation

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